Introduction to 9th grade algebra 1:
9^{th} grade Algebra 1 involves Polynomials, Arithmetic succession, Geometric succession. In Algebra 1 polynomials there are many topics like adding together, subtracting values, multiplication values and division. An Arithmetic progression is a numeral series in which every one word other than the first is obtained by adding a fixed number to the without delay preceding term.
Find the highest power in the given equation is called as degree of algebra expression. This is one of the practice of 9^{th} level students.
Ex 1:
Find and practice the zero of the polynomial from the given algebra expression P(x) = 2x + 4 at the level of 9^{th} grade.
Sol:
P(x) = 2x+4,
Plug in x = -2, then P (-2) = 2(-2) + 4 = -4+4 =0
Therefore, -2 is a zero of the polynomial 2x+4.
Ex 2:
Find and practice the problem 4 numbers between 3 and 38 which are in an A.P at the level of 9^{th} grade.
Sol:
Consider the A.P in the form a, a + d, a + 2d...
Here a = 3, and a + 5d = 38
So 5d = 35 and d = 7
The A.P. is 3, 10, 17, 24, 31, 38...
The 4 numbers between 3 and 38 are 10, 17, 24, and 31.
Ex 3:
Find and practice the problem of algebra expression at the level of 9^{th} grade (3x^{2}+4xy+5) +(9x^{2}+10xy+12).
Combine the terms which are having same powers
= (3x^{2}+9x^{2})+(4xy+10xy)+(5+12).
Adding the common power terms,
= (12x^{2})+(14xy)+(17).
So, the solution of given problem is
(12x^{2}+14xy+17).
Ex 4:
Solve and practice the algebra expression at the level of 9^{th} grade (3n^{2}+13n^{2}+5n) – (4n^{2}-8n).
Multiply the (4n^{2}-8n) by (-),
= (3n^{2}+13n^{2}+5n-4n^{2}+8n).
Combine the terms which are having same powers
=(3n^{2}+13n^{2}-4n^{2}) +(5n+8n).
=(12n^{2})+(13n).
So, the solution of given problem is(12n^{2}+13n).
Ex 5:
Determine the solution of algebra expression at the level of 9^{th} grade 2xyz (4x+3yz^{2}).
Multiply the terms,
=(2xyz)*(4x) + (2xy)*(3yz^{2}).
So, the solution of given problem is
(8x^{2}yz)+(6xy^{2}z^{2}).
These problems are sample of 9th grade practice problems.