Gre Test Preparation Classes

 

 

This article is going to help us on gre test preparation classes. Before going to discuss about gre test preparation classes let you know what is gre. Gre stands for Graduate Record Examination. There are two types of graduate record examinations, The first one is normal or general test and second one is subject test. The normal test is school admissions and subject test is grade improvement. Let we see some problems to gre  test preparation classes.

Example Problems to Gre Test Preparation Classes:

The following problems are examples for pre test preparation classes.

Gre test preparation classes - problem1) Add the following values, A = 0.980 + 45.1020 + 32.33330 + 31.0 + 0.00009

Options:

         1). 368.573
         2). 210.536299
         3). 109.41539
         4). 99.9975
         5). 80.8769543

Solution:           

             Its a simple addition but we have some decimal values.

            If the we make the order to add the above values, we get

                              0.98000

                            45.10200

                            32.33330

                            31.00000

                              0.00009    

                           109.41539   

              After adding all the values, we got  109 .41539

              Therefore the answer is (3) .

Gre test preparation classes - problem2)  joseph  needs to prepare  a cake and some candy's. The cake needs  4/9 cup of sugar and the candy's needs 2/5 cup of sugar. Joseph  has 12/15 cups of sugar. whether he has enough sugar or need more?

        A. he has enough sugar.
        B. he needs 4/12 of a cup of sugar.
        C. he needs 5/24 of a cup of sugar.
        D. he needs 2/45 of a cup of sugar.
        E. he needs 14/34 of a cup of sugar.

Soluton:

              Here we need to find , whethere Joseph needs more or not?

              Amount of sugar he has      = 12 / 15

              If he take out 4/9 and 2/6 amount from the total sugar,

                                                               = `12/15` - `4/9` +`2/5`

            If we take the L.C.M for all the denominators, we get

                                                          = `12/15` - `(20+18)/45`

                                                          = `36/45` - `38 /45`

                                                         = `(-2) /45`

             Here we have got in negative which means Joseph still needs some mroe sugar of 2/45

Ans: D. He needs 2/45 of a cup of sugar.

Gre test preparation classes-problem3) If 4x +6x +x =121 , then 7x+7 = ?

Solution:

          Here we need to find the x value to satisfy the second condition

          If we solve the first equation, we get

                         4x+6x+x =121

                                11x =121

          Divide by 11 on both sides we get

                           11x / 11 = 121 /11

                                      x = 11

          If you apply the x value in the second equation, we get

                           7x+7 = ?

                        7(11) + 7 = 77 +7

                                        = 84.

Practice Problems to Gre Test Preparation Classes:

Try to solve the following problems.

Problem1) A football team has won 14 matches and lost 20 matches. what is the ratio of the team?

Ans: 14/20

Problem2) find which one is correct  here for 5(5-6)?

            A) 10 +30

             B) 1+6

            C )  25 -30

             D) 25+30

Ans: C