This article is going to help us on gre test preparation classes. Before going to discuss about gre test preparation classes let you know what is gre. Gre stands for Graduate Record Examination. There are two types of graduate record examinations, The first one is normal or general test and second one is subject test. The normal test is school admissions and subject test is grade improvement. Let we see some problems to gre test preparation classes.

The following problems are examples for pre test preparation classes.

**Gre test preparation classes - problem1)** Add the following values, A = 0.980 + 45.1020 + 32.33330 + 31.0 + 0.00009

**Options:**

1). 368.573

2). 210.536299

3). 109.41539

4). 99.9975

5). 80.8769543

**Solution:**

Its a simple addition but we have some decimal values.

If the we make the order to add the above values, we get

0.98000

45.10200

32.33330

31.00000

0.00009

109.41539

After adding all the values, we got 109 .41539

** Therefore the answer is (3) .**

**Gre test preparation classes - problem2)** joseph needs to prepare a cake and some candy's. The cake needs 4/9 cup of sugar and the candy's needs 2/5
cup of sugar. Joseph has 12/15 cups of sugar. whether he has enough sugar or need more?

A. he has enough sugar.

B. he needs 4/12 of a cup of sugar.

C. he needs 5/24 of a cup of sugar.

D. he needs 2/45 of a cup of sugar.

E. he needs 14/34 of a cup of sugar.

**Soluton:**

Here we need to find , whethere Joseph needs more or not?

Amount of sugar he has = 12 / 15

If he take out 4/9 and 2/6 amount from the total sugar,

= `12/15` - `4/9` +`2/5`

If we take the L.C.M for all the denominators, we get

= `12/15` - `(20+18)/45`

= `36/45` - `38 /45`

= `(-2) /45`

Here we have got in negative which means Joseph still needs some mroe sugar of 2/45

**Ans: D. He needs 2/45 of a cup of sugar.**

**Gre test preparation classes-problem3)** If 4x +6x +x =121 , then 7x+7 = ?

**Solution:**

Here we need to find the x value to satisfy the second condition

If we solve the first equation, we get

4x+6x+x =121

11x =121

Divide by 11 on both sides we get

11x / 11 = 121 /11

x = 11

If you apply the x value in the second equation, we get

7x+7 = ?

7(11) + 7 = 77 +7

= 84.

**Try to solve the following problems.**

Problem1) A football team has won 14 matches and lost 20 matches. what is the ratio of the team?

**Ans: 14/20**

Problem2) find which one is correct here for 5(5-6)?

A) 10 +30

B) 1+6

C ) 25 -30

D) 25+30

**Ans: C**