Introduction to Solve Free help:
Statistics is shortly called as statics and this is used to find the arithmetic mean of the raw data. Statics is one of the important part in mathematics. This is used to calculate the mean, standard deviation, variance, and so on. Let us see about to solve statics for free
Q:1 The mark of the ten students in a school is given below: 22, 21, 38, 44, 35, 36, 33, 23, 48, 51. Can you calculate the mean marks of these students and the range of the marks of the students?
Sol:
First step arranging the ages in ascending order:
21, 22, 23, 32, 35, 36, 38, 44, 48,51
From the above we know can find the range of the students:
The range is (51  21) , that is30 marks.
Mean marks of these students (M) =Sum of observations / Total number of observation
=` (21+22+23+32+ 35+ 36+ 38+ 44+ 48+ 51)/10`
= `350/10` = 35 marks
The mean marks of the students is 35 marks.
Q:2 Calculate the mean and deviation.
X = 28, 11, 25, 24
M = `(28 + 11 + 25 + 24)/4`
= `88/4`
= 22
(ii) Then we can find the sum of (X  M) ^{2}
X 
XM 
(XM)^{2} 
28 11 25 24 
2822 = 6 1122 = 11 2522 = 3 2422 = 2 
36 121 9 2 

Total 
168 
N = 168, the total number of values.
Then N1 = 4  1
= 3
(iii) The Standard Deviation can be located by the method.
S = `sqrt((XM)^2/(N1))`
= `(sqrt168)/(sqrt3)`
= `12.96/1.73`
= 7.491
Q:3 Solve the statistics in standard deviation for the values 24, 11, 23 and 22.
Sol:
Calculate the mean and deviation.
X = 24, 11, 23 and 22
M = `(24 + 11 + 23 + 22)/4`
= `80/4`
= 20
(ii) Then we can find the sum of (X  M) ^{2}
X 
XM 
(XM)^{2} 
24 11 23 22 
2420 = 4 1120 = 9 2320 = 3 2220 = 2 
16 81 9 4 

Total 
110 
N = 4, the total number of values.
Then N1 = 4  1
= 3
(iii) The Standard Deviation can be located by the method.
S = `sqrt((XM)^2/(N1))`
= `(sqrt110)/(sqrt3)`
= `10.488/1.73`
= 6.0624
Q:4 Find out the mean, median, mode, range of the below free numbers with the help of statistics?
8,13,17,22,27,29,32.
Sol:
The given numbers are 8,13,17,22,27,29,32.
Mean
Mean with the help of average of the given number. Now need the total value of the given numbers.
Sum of the given numbers are = 8+13+17+22+27+29+32
= 148.
Now divided by 7 (Because 7 is the total given numbers) =1487
= 21.1
Median
Median is the central value of the given number series.
The number series is 8,13,17,22,27,29,32.
The central value of the above series is 22.
So we can say the median value is 22.
Mode
Mode is a copy value of the given series. Here no copy value.
So the mode value is null value.
Range
Preparation of range is the subtraction of the values form least to high of the number series.
Range = 328
= 24.